Question

determine as razões trigonométricas em cada caso.
eu preciso das contas

Answer 1

Olá,

*Seno = $\frac{cateto oposto}{hipotenusa}$

*Cosseno = $\frac{cateto adjacente}{hipotenusa}$

*Tangente = $\frac{cateto oposto}{cateto adjacente}$

Vamos ao exercício:

a) senc: $\frac{12}{13}$

cosb: $\frac{12}{13}$

tgb: $\frac{5}{12}$

b) senb: $\frac{\sqrt{2}}{\sqrt{3}}$ = $\frac{\sqrt{6}}{3}$

cosb: $\frac{1}{\sqrt{3}}$ = $\frac{\sqrt{3}}{3}$

tgc: $\frac{1}{\sqrt{2}}$ = $\frac{\sqrt{2}}{2}$

c) senb: $\frac{5}{5\sqrt{2}}$ = $\frac{\sqrt{2}}{2}$

cosb: $\frac{5}{5\sqrt{2}}$ = $\frac{\sqrt{2}}{2}$

tgb: $\frac{5}{5}$ = 1

d) senx: $\frac{8}{4\sqrt{5}}$ = $\frac{2\sqrt{2}}{5}$

cosx: $\frac{4}{4\sqrt{5}}$ = $\frac{\sqrt{5}}{5}$

tgx: $\frac{8}{4}$ = 2

e)  sen o: $\frac{16}{20}$ = $\frac{4}{5}$

cosp: $\frac{16}{20}$ = $\frac{4}{5}$

tgp: $\frac{12}{16}$ = $\frac{3}{4}$

f) senr: $\frac{1,6}{2}$ = $\frac{4}{5}$

cost: $\frac{1,6}{2}$ = $\frac{4}{5}$

tgt: $\frac{1,2}{1,6}$ = $\frac{3}{4}$