Question

determine as raízes das seguintes equaçoes ( 2° grau )

4x²-x+1=x+3x²

3x² =5x=-x-9+2x²

4+x(x-4)=x

x(x+3)-40=0

Answer 1

4x²-x+1=x+3x²
4x²-x+1-x-3x² =0
x²-2x+1 =0

Δ= 0

x1= x2= 1


3x² =5x=-x-9+2x²
3x² +5x+x+9-2x²=0
x² +6x+9=0

Δ= 0

x1= x2= - 3


4+x(x-4)=x
x² - 4x -x + 4= 0
x² - 5x +4 = 0

Δ= 9

x1= 4 ;  x2= 1


x(x+3)-40=0

x² + 3x - 40 = 0

Δ= 49

x1= 2;  x2= - 5