determine as coordenadas do ponto medio de AB, quanto
a) A= (1,7) B= ( 11,3)
b) A= (-2,5) B= (-4,-1)
c) A= (3,-1) B= (-2,1)
d) A= (1/2,1) B= ( 5/2,-4)
Soluções para a tarefa
Respondido por
5
Usando a fórmula do ponto médio M = ( xa + xb / 2 , ya + yb / 2 )
A) A(1,7) e B(11,3)
Xm = xa + xb / 2 = 1 + 11 / 2 = 12/2 = 6
Ym = ya + yb / 2 = 7 + 3 / 2 = 10/2 = 5
M(6,5)
B) Xm = -2 - 4 / 2 = -6/2 = -3
Ym = 5 - 1 / 2 = 4/2 = 2
M(-3,2)
C) Xm = 3 - 2 / 2 = 1/2
Ym = -1 + 1 = 0
M(1/2,0)
D) Xm = 1/2 + 5/2 / 2 = 6
Ym = 1 - 4 / 2 = -3/2
M(6,-3/2)
A) A(1,7) e B(11,3)
Xm = xa + xb / 2 = 1 + 11 / 2 = 12/2 = 6
Ym = ya + yb / 2 = 7 + 3 / 2 = 10/2 = 5
M(6,5)
B) Xm = -2 - 4 / 2 = -6/2 = -3
Ym = 5 - 1 / 2 = 4/2 = 2
M(-3,2)
C) Xm = 3 - 2 / 2 = 1/2
Ym = -1 + 1 = 0
M(1/2,0)
D) Xm = 1/2 + 5/2 / 2 = 6
Ym = 1 - 4 / 2 = -3/2
M(6,-3/2)
Perguntas interessantes