Question

Determine a soma da P.G infinita (1/2,1/6,1/18,...) ?

Answer 1

PG(1/2, 1/6, 1/18, ....)

a1 = 1/2

a2 = 1/6

q = a2/a1 = (1/6)/(1/2) = (1/6) x (2/1) = 2/6 = 1/3

S∞ = a1/(1 - q)

S∞ = (1/2)/(1 - (1/3))

S∞ = (1/2)/(2/3)

S∞ = (1/2) x (3/2)

S∞ = 3/4

S∞ = 0,75

Espero ter ajudado.