Question

Descubra o valor de X usando o teorema de pitágoras

Answer 1

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$a^2=b^2+c^2 \\ \\ (x+1)^2=( \sqrt{7} )^2+x^2 \\ x^2+2x+1=7+x^2 \\ \not x^2-\not x^2+2x=7-1 \\ 2x=6 \\ x=6\div2 \\ x=3$