Question

derivada de e^sen -1 ???

Answer 1

$f(x)=e^{\sin^{-1}(x)}\\\\u=\sin^{-1}(x)\\\\u'=\frac{1}{\sqrt{1-x^2}}\\\\f'(x)=f'(u)\cdot u'\\\\f(u)=e^u\\\\f'(u)=e^u\\\\f'(x)=e^u\cdot\frac{1}{\sqrt{1-x^2}}=\boxed{\frac{e^{\sin^{-1}(x)}}{\sqrt{1-x^2}}}$