Question

Dentre os numeros numeros abaixo quais sao raiz da equaçao x2-5x+6=0

Answer 1

$x^2-5x+6=0$

Coeficientes: a = 1, b = -5 e c = 6

$\Delta=b^2-4ac\\\Delta=(-5)^2-4\cdot1\cdot6\\\Delta=25-24\\\Delta=1$

$x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{-(-5)\pm\sqrt{1}}{2\cdot1}\\\\x=\dfrac{5\pm1}{2}\\\\x_1=\dfrac{5+1}{2}=\dfrac{6}{2}=3\\\\x_2=\dfrac{5-1}{2}=\dfrac{4}{2}=2$



Espero ter ajudado.
Bons estudos! :)