Question

• Demonstre que:
$- \cotg(x) + \frac{1}{ \sin(x)} = \tg \left( \frac{x}{2} \right)$
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Answer 1

-cotg(x) + 1/sin(x) = tg(x/2)

-cotg(x) + 1/sin(x) = tg × x/2

-cotg(x) + cscx = tg × x/2

-cotg(x) + cscx = tgx/2

(-cotg(x) + cscx) × 2 = tgx

2(-cotg(x) + cscx) = tgx

2(-cotg(x) + cscx)/g = tx

2(-cotg(x) + cscx)/g /x = t

2(-cotg(x) + cscx)/gx = t

t = 2(-cotg(x) + cscx)/gx