Question

Dados a =6 , b= - 5 e c = 1, calcule o número real x tal que x= - b + ( sinal de raiz , quadrada, b² - 4 ac
                        2 a

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Answer 1

$x = \frac{-b + \sqrt{b^2 - 4ac}}{2a} \\\\ x = \frac{-(-5) + \sqrt{(-5)^2 - 4 \cdot 6 \cdot 1}}{2 \cdot 6} \\\\ x = \frac{5+ \sqrt{25-24}}{12} \\\\ x = \frac{5+1}{12} \\\\ x = \frac{6}{12} \\\\ x = \frac12$