Question

dado a função quadratica f (x)=3x2 - 4X+1 DETERMINE

Answer 1

3x^2-4x+1=0
delta=b^2-4.a.c
delta=(-4)^2-4.3.1
delta=16-12
delta=4
x=-b-/+ raiz de delta / 2a
x=-(-4)-2/2.3
x=4-2/6
x=2/6 (:2)
x=1/3
x=-(-4)+2/2.3
x=4+2/6
x=6/6
x=1