Question

dadas as retas de equaçoes (k-1)x+3y-1=0 e 2ky-2y+5=0, os valores de k para os quais as retas sao paralelas é:

Answer 1

(k-1)x+3y-1=0

(k-1)x - 1 = -3y

y = [ (k-1)x - 1 ] / -3

y = [(k-1)/-3]*x + 1/3

coeficiente angular = (k-1)/-3

2kx-2y+5=0

2kx + 5 = 2y

y = 2kx/2 + 5/2

y = kx + 5/2

coeficiente angular = k

Igualando os coeficientes angulares:

k = (k-1)/-3

-3k = k-1

1 = 4k

k = 1/4