dadas a coodernadas da vertice de um triangulo ABC calcule as coordenada de seu baricentro no caso a,A(-1,2 ) ,B(0,-5) e C (7-6)
b A(1,5) B(6,2) e C(2,-2)
Soluções para a tarefa
Respondido por
2
Caso A
Xg = Xa + Xb + Xc / 3
Xg = -1 + 0 + 7 / 3
Xg = 6 / 3
Xg = 2
Yg = Ya + Yb + Yc / 3
Yg = 2 - 5 - 6 / 3
Yg = -9 / 3
Yg = -3
G (2, -3)
Caso B
Xg = Xa + Xb + Xc / 3
Xg = 1 + 6 + 2 / 3
Xg = 9 / 3
Xg = 3
Yg = Ya + Yb + Yc / 3
Yg = 5 + 2 - 2 / 3
Yg = 5 / 3
G (3, 5/3)
Xg = Xa + Xb + Xc / 3
Xg = -1 + 0 + 7 / 3
Xg = 6 / 3
Xg = 2
Yg = Ya + Yb + Yc / 3
Yg = 2 - 5 - 6 / 3
Yg = -9 / 3
Yg = -3
G (2, -3)
Caso B
Xg = Xa + Xb + Xc / 3
Xg = 1 + 6 + 2 / 3
Xg = 9 / 3
Xg = 3
Yg = Ya + Yb + Yc / 3
Yg = 5 + 2 - 2 / 3
Yg = 5 / 3
G (3, 5/3)
Perguntas interessantes