Question

Dada função f : R -> R definida por f(x) x²- 9x + 14, determina a) f(-3) b) f(0) c) (7)

Answer 1

f(x)=x²-9x+14
f(-3)=(-3)²- 9.(-3) + 14
f(-3)=9+27+ 14
f(-3)=50


f(x)=x²-9x+14
f(0)=0²-9.0+14
f(0)=14

f(x)=x²-9x+14
f(7)=7²-9.7+14
f(7)=49-63+14
f(7)=-14+14
f(7)=0

Answer 2

$f(x) = x^2 -9x+14 \\\\ f(-3) = (-3)^2-9\cdot(-3) + 14 \\ f(-3)=9+27+14\\ f(-3) = 50 \\\\ f(0) = 0^2 - 9 \cdot 0 + 14 \\ f(0)=0 + 0 + 14 \\ f(0) = 14 \\\\ f(7) = 7^2 -9 \cdot 7 +14 \\ f(7)= 49-63+14 \\ f(7) = 0$