Question

Dada a PG(1, 2, 4, ..., 1024), calcule a soma dos seus termos.​

Answer 1

q^n-1 = an/a1

2^n-1 = 1024/1

2^n-1 = 2¹⁰

n-1 = 10. ===> n=11

s = a1.(q^n - 1) / q-1

s = 1.(2¹¹ - 1) /2-1

s = (2048 - 1)

s = 2047