Question

Dada a função quadrática f(x)=3x²-4x+1:

a)f(1)

b)f(√2)

Answer 1

f(x)=3x²-4x+1:

a)f(1)= 3(1)²-4(1)+1= 3 - 4 + 1 = 0

b)f(√2) = 3(V2)²-4(V2)+1=3.2 - 4V2 + 1 = 6+1 - 4V2 ==> 7 - 4V2 

Answer 2

F (1)=3.1²-4.1+1= 0
F(√2)= 3(√2)²-4√2+1
F(√2)= 3.2-4√2+1
F(√2)= 6-4√2+1
F(√2) = 7-4√2