Question

Dada a função afim f(x)=4x+3, determine os valores de x para que :
a) f(x)=1
b)f(x)=0
c)f(x)= 1/3

Answer 1

vamos lá...

$f(x)=4x+3 \\ \\ a) \\ f(x)=1 \\ 4x+3=1 \\ 4x=1-3 \\ 4x=-2 \\ \\ x=- \frac{2}{4}=- \frac{1}{2}$ 

$b) \\ f(x)=0 \\ \\ 4x+3=0 \\ 4x=-3 \\ x=- \frac{3}{4}$ 

$c) \\ f(x)= \frac{1}{3} \\ \\ 4x+3= \frac{1}{3} \\ \\ mmc=3 \\ \\ 12x+9=1 \\ 12x=1-9 \\ 12x=-8 \\ \\ x=- \frac{8}{12}=- \frac{2}{3}$

Answer 2

F(1)= 4.1+3
F(1)=4+3
F(1)=7

F(0)=4.0+3
F(0)=0+3
F(0)=3

F(1/3)=4.1/3+3
F(1/3)=4/3+3