dada a finita da cinco termos onde a1=-48 e q=1/2, determine a soma dos termos desta pg
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n = 5
S n = a 1 . (q^n - 1 ) / 1 - q
S 5 = - 48 . (1/2)^5 - 1 / 1/2 - 1
S 5 = -48 . 1/32 - 1 / 1/2 - 1
S 5 = -48/ 32 - 1 / 1/2 - 2/2
S 5 = -48/32 - 32/32 / -1/2
S 5 = -80/32 / - 1/2
S 5 = -80/32 . -2/1
S 5 = 160/32
S 5 = 5
S n = a 1 . (q^n - 1 ) / 1 - q
S 5 = - 48 . (1/2)^5 - 1 / 1/2 - 1
S 5 = -48 . 1/32 - 1 / 1/2 - 1
S 5 = -48/ 32 - 1 / 1/2 - 2/2
S 5 = -48/32 - 32/32 / -1/2
S 5 = -80/32 / - 1/2
S 5 = -80/32 . -2/1
S 5 = 160/32
S 5 = 5
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