Question

Cubo da soma ou da diferença de dois termos
desenvolver:
1) (x+2)³ =
2) (x-3)³ =
3) (x-4)³=
4) (x+2)²=
5) (x-10)²=
6) (x+5)²=
7) (x-11)³=
8) (x+11)²=
9) (x-1)³=
10) (x+1)³=

ME AJUDEMM POR FAVOR!!!!!!!

Answer 1

1.(x+2)³

=(x+2)(x²+2•x•2+2²)

=(x+2)(x²+4x+4)

=x³+4x²+4x+2x²+8x+8

=x³+4x²+2x²+4x+8x+8

=x³+6x²+12x+8

2.(x—3)³

=(x—3)(x²—2•x•3+3²)

=(x—3)(x²—6x+9)

=x³—6x²+9x—3x²+18x—27

=x³—6x²—3x²+9x+18x—27

=x³—9x²+27x—27

3.(x—4)³

=(x—4)(x²—2•x•4+4²)

=(x—4)(x²—8x+16)

=x³—8x²+16x—4x²+32x—64

=x³—8x²—4x²+16x+32x—64

=x³—12x²+48x—64

4.(x+2)²

x²+2•x•2+2²

(x²+4x+4)

5.(x—10)²

=x²—2•x•10+10²

=x²—20x+100

6.(x+5)²

=(x²+2•x•5+5²)

=x²+10x+25

7.(x—11)²

=x²—2•x•11+11²

=x²—22x+121

8.(x+11)³

=(x+11)(x²+2•x•11+11²)

=(x+11)(x²+22x+121)

=x³+22x²+121x+11x²+242x+1331

=x³+22x²+11x²+121x+242x+1331

=x³+33x²+363x+1331

9.(x—1)³

=(x—1)(x²—2•x•1+1²)

=(x—1)(x²—2x+1)

=x³—2x²+x—x²+2x—1

=x³—2x²—x²+x+2x—1

=x³—3x²+2x—1

10.(x+1)³

=(x+1)(x²+2•x•1+1²)

=(x+1)(x²+2x+1)

=x³+2x²+x+x²+2x+1

=x³+3x²+3x+1

Espero ter ajudado bastante:)