considerando o polinômio P(x) = 2x²-x=1, calcule:
a) P=(-1)
b)P(1/2)
c)P=(0)
Soluções para a tarefa
Respondido por
54
P(x) = 2x² - x + 1
P(- 1) = 2.(-1) - (- 1) + 1
P(-1) = - 2 + 1 + 1
P(- 1) = - 2 + 2
P(- 1) = 0
-----------------------------------------------
P(x) = 2x - x + 1
2 1 1 1
P(1/2) = -----.----- - ---- + -----
1 2 2 1
2 1 1
P(1/2) = ------- - ----- - ------
2 2 1
1 1
P(1/2) = ----- - -------
2 1 mmc = 2
1 2
P(1/2) = ----- - -----
2 2
1
P(1/2) = - -----
2
--------------------------------------------------------------------------------------
P(0) = 2x² - x + 1
P(0) = 2.0² 0 - 0 + 1
P(0) = 1
P(- 1) = 2.(-1) - (- 1) + 1
P(-1) = - 2 + 1 + 1
P(- 1) = - 2 + 2
P(- 1) = 0
-----------------------------------------------
P(x) = 2x - x + 1
2 1 1 1
P(1/2) = -----.----- - ---- + -----
1 2 2 1
2 1 1
P(1/2) = ------- - ----- - ------
2 2 1
1 1
P(1/2) = ----- - -------
2 1 mmc = 2
1 2
P(1/2) = ----- - -----
2 2
1
P(1/2) = - -----
2
--------------------------------------------------------------------------------------
P(0) = 2x² - x + 1
P(0) = 2.0² 0 - 0 + 1
P(0) = 1
Respondido por
80
P(x) = 2x²-x+1, calcule:
a) P=(-1) ==> 2(-1)² - (-1) + 1==. 2.1 + 1 + 1 ==> 2+2 ==> 4
===================================================
b)P(1/2) ==> 2(1/2)² - (1/2) + 1==> 2.1/4 - 1/2 + 1
2 - 1 + 1 ==> 2 - 2 + 4 ==> 4 ==> 1
4 2 4 4
===========================================
c)P=(0)
==> 2(0)² - (0) + 1==> 2.0 - 0 + 1 ==> 0+1 ==> 1
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