Question

como resolver a funçao :    -2x²-4x+2=0

Answer 1

$-2x^2-4x+2=0\;\;\div(-2\\\\x^2+2x-1=0\\\\\Delta=4+4$

$x=\frac{-2\pm\sqrt{8}}{2}\\\\x=\frac{-2\pm2\sqrt{2}}{2}$

$\boxed{x'=-1+\sqrt{2}}\\\\\boxed{x''=-1-\sqrt{2}}$