Question

como resolver? (2x+)²-5(2x=1)+4=0

Answer 1

(2x+1)² -5(2x+1) + 4 = 0
4x² + 1 - 10x - 5 + 4 = 0
4x² - 10x - 5 + 4 + 1 = 0
4x² - 10x - 5 + 5 = 0
4x² - 10x  = 0
2x² (2x - 5) = 0
2x - 5 = 0
2x = 5
x = $\frac{5}{2}$