Question

Como faço para resolver o polinômio (x³-y³).(x+y)-(x²+y²).x²-y²) na forma mais simples possível?

Answer 1

(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x-y)(x²+xy+y²).(x+y) - (x²+y²).(x²-y²)

(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x-y).(x+y).(x²+xy+y²) - (x²+y²).(x²-y²)

(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).(x²+xy+y²) - (x²+y²).(x²-y²)

(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).[x²+xy+y² - (x²+y²)]

(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).[x²+xy+y² - x²-y²]

(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).xy