Question

Como eu resolvo (4x-3) (x+5) = 0 ?

Answer 1

(4x-3) (x+5) = 0
4x²+20x-3x-15=0
4x²+17x-15 =0
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Encontrando as raizes

Δ=17²-4.4.(-15)
Δ=289+240
Δ=529

X=-17±√529/2.4
X=-17±23/8
X¹=-17+23/8=6/8=0,75
X²=-17-23/8=-40/8=-5

S={-0,75 ; 5 }
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Espero ter ajudado ! :-)