Question

Como determinar as raizes da equação x ² - x/10-1/5=0?

Answer 1

$x^2-\frac{x}{10}-\frac{1}{5}=0$

${\color{blue}{10x^2-x-2=0}}$

Onde:

a=10 ; b=-1 e c=-2

Lembrando que:

∆ = b²—4•a•c

∆ = (—1)²—4•10•(—2)

∆ = 1+80

∆ = 81

Bhaskara:

$\large\boxed{\boxed{{x_{1,2}=\frac{-b\pm\sqrt{\Delta}}{2*a}}}}}}$

$x_{1,2}=\frac{1\pm\sqrt{81}}{2*10}=\frac{1\pm\:9}{20}$

$x_{1}=\frac{1+9}{20}=\frac{10}{20}=\frac{1}{2}$

$x_{2}=\frac{1-9}{20}=\frac{-8}{20}=\frac{-2}{5}$