Question

como calcular esta equação completa
(x+3)(x-4)-52= - x

Answer 1

(x+3)(x-4)-52= - x
x^2 - 4x + 3x - 12 - 52 + x = 0
x^2 - 64 = 0
x^2 = 64
x = +- √64
x = +- 8

S = { 8 ; - 8 }

Answer 2

$(x+3)*(x-4)-52=-x \\ \\ (x+3)*x-(x+3)*4-52=-x \\ \\ x*x+3x-(x+3)*4-52=-x \\ \\ x^{2} +3x-(x+3)*4-52=-x \\ \\ x^{2} +3x-x*4-3*4-52=-x \\ \\ x^{2} +3x-x*4-12-52=-x \\ \\ x^{2} +3x-x*4-64=-x \\ \\ x^{2} -x-64=-x \\ \\ x^{2} -x-64-(-x)=0 \\ \\ x^{2} -x-(-x)=0+64 \\ \\ x^{2} =64 \\ \\ x_{1,2} = \± \sqrt{64} \\ \\ x_{1,2} = \±8$