Question

Como calcular essas equações sendo U = IR

 

a)$<var>\sqrt[3]{x+1}=3</var>$

 

b)$<var>x-3=2\sqrt{x}</var>$

 

c)$<var>\sqrt{5+\sqrt{3x-2}}=3</var>$

 

d)$<var>\sqrt[5]{2-\sqrt[3]{2x-1}}=1</var>$

 

 

 

 

Obrigada :)

Answer 1

$\sqrt[3]{x+1}=3 \rightarrow x+1=27 \rightarrow x=27-1 \rightarrow x=26$

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$x-3=2\sqrt3 \rightarrow x=2\sqrt3+3$
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$\sqrt{5+\sqrt{3x-2}}=3 \rightarrow 5+\sqrt{3x-2}=9 \rightarrow \sqrt{3x-2}=9-5$

$\sqrt{3x-2}=9-5 \rightarrow \sqrt{3x-2}=4 \rightarrow 3x-2=16 \rightarrow 3x=15 \rightarrow x=5$

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$\sqrt[5] {2-\sqrt[3]{2x-1}}=1 \rightarrow 2-\sqrt[3]{2x-1}=1 \rightarrow \sqrt[3]{2x-1}=1$


$\sqrt[3]{2x-1}=1 \rightarrow 2x-1=1 \rightarrow 2x=2 \rightarrow x=1$