Question

Calcule:
(x²-1)²=
(9x²-1)²=
(x-5y3)²=
(1-mx)²=
(a³-m³)²=
(2n⁴-1)²=
(-3x-5)²=

Answer 1

(x²-1)²=
(x²)² -2.(x²).(1) + (1)²
x⁴ -2x² +1

ou

(x²-1) . (x²-1)
x⁴ -x² -x² +1
x⁴ -2x² +1


(9x²-1)²=
(9x²)² -2.(9x²).(1) + (1)²
81x⁴ -18x² +1
 ou

((9x²-1)  . (9x²-1)
81x⁴ - 9x² -9x² +1
81x⁴ -18x² +1


(x-5y3)²
(x)² -2.(x).(5y) +(5y³)²
x² -10xy³ +25y⁶

ou 

(x-5y3) . (x-5y3)
x² -5xy³ -5xy³ +25y⁶
x² -10xy³ +25y⁶



(1-mx)²=
(1)² -2.(1).(mx) +(mx)²
1 -2mx +m²x²

ou

(1-mx) . (1-mx)
1 -mx -mx +m²x²
1-2mx +m²x²



(a³-m³)²=
(a³)² -2.(a³).(m³) + (m³)²
a⁶ -2a³m³ + m⁶

ou

(a³-m³) . (a³-m³)
a⁶ -a³m³ -a³m³ +m⁶
a⁶ -2a³m³ +m⁶


(2n⁴-1)²=
(2n⁴)² -2.(2n⁴).(1) +(1)²
4n⁸ -4n⁴ +1

ou

(2n⁴-1) . (2n⁴-1)
4n⁸ -2n⁴ -2n⁴ +1
4n⁸ -4n⁴ +1



(-3x-5)²=
(-3x)² -2.(-3x).(5) + (5)²
9x² +30x +25

ou

(-3x-5) . (-3x-5)
9x² +15x +15x +25
9x² +30x +25