Question

calcule os produtos
a) ( x + 5 ) ( x + 2 )=
b) (3 x + 2 ) (2 x + 1)=
c) ( x + 7 ) ( x - 4) =
d) ( 3 x + 4) ( 2 x - 1 ) =
e) ( x - 4 ) ( x - y ) =
f) ( 5 x - 2 ( 2 x - 1 )=
g) ( 3 x + 1 ) ( 3 x 1 ) =
h) ( 2 x + 5 ( 2 x - 5 ) =

Answer 1

Resposta:

Explicação passo a passo:

$a)$

$(x+5).(x+2)=$

$x^{2} +2x+5x+10=$

$x^{2} +7x+10$

$b)$

$(3x+2).(2x+1)=$

$6x^{2} +3x+4x+2=$

$6x^{2} +7x+2$

$c)$

$(x+7).(x-4)=$

$x^{2} -4x+7x-28=$

$x^{2} +3x-28$

$d)$

$(3x+4).(2x-1)=$

$6x^{2} -3x+8x-4=$

$6x^{2} +5x-4$

$e)$

$(x-4).(x-y)=$

$x^{2} -xy-4x+4y=$

$f)$

$(5x-2).(2x-1)=$

$10x^{2} -5x-4x+2=$

$10x^{2} -9x+2$

$g)$

$(3x+1).(3x+1)=$

$9x^{2} +3x+3x+1=$

$9x^{2} +6x+1$

$h)$

$(2x+5).(2x-5)=$

$4x^{2} -10x+10x-25=$

$4x^{2} -25$