Question

calcule o decimo termo da p.g onde: 3,6,9

Answer 1

$a_1=3 \\ a_2=6 \\ a_3=9 \\ n=10 \\ q=6:3=2 \\ \\ a_1_0=a_1*q^{n-1} \\ a_1_0=3*2^{10-1} \\ a_1_0=3*2^9 \\ a_1_0=3*512 \\ a_1_0=1536$

Espero ter ajudado. Valeu!

Answer 2

a10= a1*q^n-1
a10= 3*2^10-1
a10=3*2^9
a10=3*512
a10=1536