Question

Calcule a soma dos 15 primeiros termos da PG 3,6,12,24

Answer 1

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ a1 = 3 \\ a2 = 6 \\ n = 15 \\ q = \frac{a2}{a1} = \frac{6}{3} = 2 \\ \\ = = = = = = = = = = = = = = = = \\ \\ > \: soma \: dos \: 15 \: primeiros \\ termos \: da \: pg \\ \\ sn = \frac{a1(q {}^{n} - 1)}{q - 1} \\ \\ sn = \frac{3(2 {}^{15} - 1) }{2 - 1} \\ \\ sn = \frac{3(32768 - 1)}{1} \\ \\ sn = \frac{3 \times 32767}{1} \\ \\ sn = 98301 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant$