Question

calcule a distância entre os pontos:
a) P(6,3) e Q(-4,-5)
b) N(0,-8) é V(5,5)

Answer 1

Olá!!

Resolução!!

a )

P ( 6, 3 ) e Q ( - 4, - 5 )

`````````````__________________
PQ = √ ( x2 - x1 )² + ( y2 - y1 )²
`````````````__________________
PQ = √ ( - 4 - 6 )² + ( - 5 - 3 )²
``````````````_____________
PQ = √ ( - 10 )² + ( - 8 )²
``````````````________
PQ = √ 100 + 64

PQ = √164

164 | 2
82 | 2
41 | 41
1

√164 → √2² • 41 → 2 • √41 → 2√41

PQ = √164

PQ = 2√41

R = A distancia é 2√41 unidades

b)

N ( 0, - 8 ) e V ( 5, 5 )

``````````````__________________
NV = √ ( x2 - x1 )² + ( y2 - y1 )²
``````````````_________________
NV = √ ( 5 - 0 )² + ( 5 - ( - 8 )²
``````````````_______________
NV = √ ( 5 - 0 )² + ( 5 + 8 )²
``````````````_______
NV = √ 5² + 13²
``````````````________
NV = √ 25 + 169

NV = √194

R = A distância é √194 unidades

Espero ter ajudado!