Question

-calcule
a)(2xy^4)^3
b)(-4a ^2b)^2
-resolva as equações
d)-4y-5-1=20
c)4y+8=2-3y

Answer 1

-calcule :

a)(2xy^4)^3=>

2^3 x^3 *(y^4)^3

8x^3y^12


b)(-4a ^2b)^2=>

(-4)^2.(a^2)^2 .b^2

16a^4 b^2




d)-4y-5-1=20 =>

-4y-6=20

-4y=20+6

-4y=26

y= -13/2





c)4y+8=2-3y=>

4y+3y=2-8

7y= -6

y= -6/7