Question

Calcule:

1)
$\frac{6}{5} + \frac{8}{5}$
2)
$\frac{4}{9} - \frac{2}{9}$
3)
$\frac{7}{3} + \frac{3}{4}$
4)
$\frac{5}{8} + \frac{1}{6}$
5)
$\frac{3}{7} + \frac{2}{7} + \frac{13}{9}$
6)
$\frac{1}{2} + \frac{7}{4} + \frac{1}{4}$
​

Answer 1

Resposta:

$1)\\ \\ \frac{6}{5}+ \frac{8}{5}= \frac{6+8}{5}= \frac{14}{5} \\ \\ 2)\\ \\ \frac{4}{9}- \frac{2}{9}= \frac{4-2}{9}= \frac{2}{9} \\ \\ 3)\\ \\ \frac{7}{3} +\frac{3}{4}=\\ \\ m.m.c.=12\\ \\ \frac{(12:3*7)+(12:4*3)}{12} =\frac{28+9}{12} =\frac{37}{12} \\ \\ 4)\\ \\ \frac{5}{8} +\frac{1}{6}=\\ \\ m.m.c.=24\\ \\ \frac{(24:8*5)+(24:6*1)}{24} =\frac{15+4}{24} =\frac{19}{24}$

$5)\\ \\ \frac{3}{7} +\frac{2}{7} +\frac{13}{9} =\\ \\ m.m.c.=63\\ \\ \frac{(63:7*3)+(63:7*2)+(63:9*13)}{63} =\frac{27+18+91}{63} =\frac{136}{63} \\ \\ 6)\\ \\ \frac{1}{2} +\frac{7}{4} +\frac{1}{4} =\\ \\ m.m.c.=4\\ \\ \frac{(4:2*1)+(4:4*7)+(4:4*1)}{4} =\frac{8+7+1}{4} =\frac{16}{4}=16:4=4$