Question

As raízes da equação -x - (3p+1)x + 2p=0

Answer 1

x2 = (3 - 1)/4 = 1/2. podemos afirmar que ela possui duas raízes reais e distintas

Answer 2

Resposta:

$x=\frac{-(3p+1)-\sqrt{9p^2+14p+1} }{2}\\ou\\x=\frac{-(3p+1)+\sqrt{9p^2+14p+1} }{2}$

Explicação passo a passo:

-x² - (3p + 1)x + 2p = 0

x² + (3p + 1)x - 2p = 0

$\Delta=b^2-4ac\\\\\Delta=(3p + 1)\²-4.1(-2p)\\\\\Delta=9p^}2+6p+1+8p\\\\\Delta=9p^2+14p+1\\\\x=\frac{-b\pm\sqrt{\Delta} }{2a}\\\\x=\frac{-(3p+1)\pm\sqrt{9p^2+14p+1} }{2.1} \\\\x=\frac{-(3p+1)-\sqrt{9p^2+14p+1} }{2}\\ou\\x=\frac{-(3p+1)+\sqrt{9p^2+14p+1} }{2}$