Question

Aplicando as relaçoes metricas no triangulo retangulo , calcule o valor do x:

Answer 1

a) b² = am
   16² = 12,8.x
   256 = 12,8x --> x = 256 : 12,8 --> x = 20
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b) c² = an
    a = 15 + 5 = 20
    n = 5
  x² = 20 . 5 -->x² = 100 --> x = √100 --> x = 10
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c) h² = m.n
    12² = 9x
    144 = 9x --> x = 144 : 9 --> x = 16
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d) ah = bc
    8x = 5√39
      x = 5/8√39
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e) xh = bc
    4,8x = 6 . 8
    4,8x = 48 --> x = 48 : 4,8 --> x = 10