Question

Alguém poderia responder a alternativa D pra mim?
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Answer 1

d)1x²/4 + 5x/4 -6 = 0

a=1/4

b=5/4

c=-6

a formula de baskara eh;

x= -b±√∆/2a

∆=b²-4ac

∆=(5/4)² -4(1/4)(-6)

∆=25/16 +6 = 25 +96/16 = 121/16

x'= (-5/4 +√121/16)/2(1/4)

x'= (-5/4 +11/4)/(2/4)

x'= (6/4)/(2/4)

x'= 6/2

x'=3

x"=(-5/4 -√121/16)/2(1/4)

x"=(-5/4-11/4)/(2/4)

x"=(-16/4)/(2/4)

x"=-16/2

x"=-8

s={-8,3}

Answer 2

Resposta:

S = { x ∈ R | x = -8 ou x = 3}

Explicação passo-a-passo:

Fazendo M.M.C $\frac{x^{2} + 5x - 24 = 0}{4}$

x² + 5x - 24 = 0

Δ = b² -4ac

Δ = 25 + 96

Δ = 121

x = -b ±√Δ/2a

x' = -5 + 11 / 2

x' = 3

x'' = -5 - 11 /2

x'' = -8