Question

alguém mim ajudar 4x4+4=17x2

Answer 1

Passa o 17x² pro outro lado:
4x⁴ - 17x² + 4 = 0

y = x²

4y² - 17y + 4 = 0

bhaskara
b² - 4ac
-17² - 4.4.4
289 - 64
225 = delta

-b +/- √Δ / 2a
-(-17) +/- √225 / 2.4
17 +/- 15 / 8

y1 = 17 + 15 / 8 = 32/8 = 4
y2 = 17 - 15/8 = 2/8 = 1/4

Agr trocando:

x1 = √y1 = √4 = 2
x2 = -√y1 = -√4 = -2
x3 = √y2 = √1/4 = 1/2
x4 = -√y2 = -√1/4 = -1/2

Answer 2

Resposta:

$4x^4+4=17x^2\\\\4x^4+4-17x^2=17x^2-17x^2\\\\4x^4-17x^2+4=0\\\\4u^2-17u+4=0\\\\U=X\\\\4u^2-17u+4=0\\\\x=2,\:x=-2,\:x=\frac{1}{2},\:x=-\frac{1}{2}$