Question

alguem me ajuda pelo amor de deus

Answer 1

Resposta:

Explicação passo a passo:

$1)$

$a)$

$(+3x^{2})^{2} =9x^{4}$

$b)$

$(-8x^{4})^{2} =64x^{8}$

$c)$

$(2x^{5})^{3}=8x^{15}$

$d)$  

$(3a^{2})^{3}=27a^{6}$

$e)$

$(-y^{2})^{4} =y^{8}$

$f)$

$(-mn)^{4} =m^{4} n^{4}$

$g)$

$(2xy^{2} )^{4} =16x^{4}y^{8}$

$h)$

$(-4a^{2}b)^{2} =16a^{4} b^{2}$

$i)$

$(-3a^{2}) ^{3} =-27a^{6}$

$j)$

$(-6m^{3})^{2} =36m^{6}$

$k)$

$(-3x^{3}y^{4}) ^{4}=81x^{12} y^{16}$

$l)$

$(-2a^{2}m^{3})^{3} =-8a^{6} m^{9}$

$2)$

$a)$

$(\frac{a^{2} }{2}) ^{3} =\frac{a^{6} }{8}$

$b)$

$(-\frac{x^{2} }{4}) ^{2} =\frac{x^{4} }{16}$

$c)$

$(-\frac{1}{2}a) ^{2} =\frac{1}{4}a^{2}$

$d)$

$(\frac{2}{3} x)^{3}=\frac{8}{27} x^{3}$

$e)$

$(-\frac{3}{4}m) ^{3} =-\frac{27}{64}m^{3}$

$f)$

$(-\frac{5}{6}m^{3}) ^{2} =\frac{25}{36} m^{6}$