Question

alguém me ajuda aqui (deixem os cálculos )

Answer 1

$log_{2}( {x}^{2} ) + log_{4}( \sqrt{x} ) = - 2.25 \\ \\ 2 log_{2}(x) + log_{ {2}^{2} }( {x}^{ \frac{1}{2} } ) = - \frac{9}{4} \\ \\ 2 log_{2}(x) + \frac{1}{2} \times \frac{1}{2} log_{2}(x) = - \frac{9}{4} \\ \\ 2 log_{2}(x) + \frac{ log_{2}(x) }{4} = - \frac{9}{4} \\ \\ \frac{9 log_{2}(x) }{4} = - \frac{9}{4} \\ \\ log_{2}(x) = - 1 \\ \\ x = {2}^{ - 1} \\ \\ x = \frac{1}{2} \\ \\ x = 0.5$