Question

alguem me ajuda a responder x2 -2x-6

Answer 1

Resolvendo pela fórmula de Bhaskara, temos:

$x^2-2x-6=0 \\ \\ delta=(-2)^2-4.1.(-6)=4+24=28 \\ \\ \sqrt{delta} = \sqrt{28} = \sqrt{2^2.7} =2 \sqrt{7} \\ \\ x_{1} = \frac{2+2 \sqrt{7} }{2} = \frac{2}{2} + \frac{2 \sqrt{7} }{2} =1+ \sqrt{7} \\ \\ x_{2} = \frac{2-2 \sqrt{7} }{2} =1- \sqrt{7}$

S {1-$\sqrt{7}$,1+$\sqrt{7}$}

Answer 2

$x^{2} -2x-6=0\\(-2) ^{2} -4*(1)*(-6)\\4+24=28\\\\ \frac{-(-2)+- \sqrt{28} }{2}\\\\ \frac{2+- \sqrt{28} }{2} \\\\x'= \frac{2+ \sqrt{28} }{2} \\\\x''= \frac{2- \sqrt{28} }{2}$