Question

alguém consegue responder a 4 e a 5 pra mim?

Answer 1

4) a) log₂64 = x => 2 ^x = 2⁶ => x = 6
     b) log₆₂₅∛25 = y => log₆₂₅∛5²=y => 625^y = 5²/³ => (5^4)^y= 5²/³
         5^4y = 5²/³ => 4y =2/3 => y = 2/12 => y = 1/6

Answer 2

Olá Paulo

4)

log2(64) = x

2^x = 64 = 2^6

x = 6

log625(³√25) = x

625^x = ³√25

5^4x = 5^(2/3)

4x = 2/3

x = 2/12

x = 1/6

5)

log4(128/4) = log4(32) 

log4(32) = x

4x = 32

2^2x = 2^5 

2x = 5

x = 5/2

log3(243*81) = log3(243) + log3(81) 

3^x = 243 = 3^5 
x = 5 

3^y = 81 = 3^4
y = 4

log3(243*81) = x + y = 5 + 4 = 9