Question

Algueem podee miim ajudaar prfv...!

Answer 1

Usando o teorema de Pitagoras:

d² = 6²+ 6²
d² = 36+36
d² = 72
d = $\sqrt{72}$
d = 2*3$\sqrt{2}$
d = 6 $\sqrt{2}$

Answer 2

h² = c² + c²
h² = 6² + 6²
h² = 36 + 36
h = √72 ⇒ h = 6√2 ← Alternativa C