Question

algem me ajuda a resolver essas equações de 1 grau com umaincógnita em R

y-384=700

6x-19=71+x

9n+37=40

3y-20=y+80

3x+7=34

8-7x=14-10x

2(x+5)=2-3(2+3x)+15

5k=15

3(x-2)x2(4x-3)-5(2-X)=6(x=3)x2x

7x-3=3x

Answer 1

y-384=700 ==. y = 700+ 384 ==> y =  1084
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6x-19=71+x ==> 6x-x = 71+19==> 5x=90 ==> x=18
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9n+37=40==> 9n = 40- 37 ==> 9n = 3 ==> n = 3/9 ou n = 1/3
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3y-20=y+80==> 3y-y=80+20==> 2y=100==> y = 50
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3x+7=34==> 3x= 34-7 ==> 3x=27==> x= 9

8-7x=14-10x==> -7x+10x = 14-8==> 3x=6 ==> x = 2
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2(x+5)=2-3(2+3x)+15
 2x+10=2-6 -9x +x+15

2x+9x-x = 2-6+15-10 ==> 10x= 1==> x = 1/10 ou x = 0,1
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5k=15 ==> k = 3

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3(x-2)x2(4x-3)-5(2-X)=6(x=3)x2x   <=== como estar nao sera equacao do 1grau

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7x-3=3x ==> 7x - 3x = 3 ==> 4x = 3 ==> x = 3/4