Question

AJUDA AI GALERA COM O CALCULO NESSA QUESTÃO

Answer 1

a)
$\boxed{(-\frac{1}{6}).(-\frac{2}{5})=\frac{1}{15}}$

b)
$\boxed{\frac{\frac{1}{3}}{\frac{1}{2}}=\frac{1}{3}.\frac{2}{1}=\frac{2}{3}}$

c)
$\boxed{\frac{2}{3}:(-\frac{1}{5})=\frac{2}{3}.(-5)=-\frac{10}{3}}$

d)
$\boxed{\frac{1}{3}:\frac{2}{3}.\frac{1}{4}=\frac{1}{3}.\frac{3}{2}.\frac{1}{4}=\frac{1}{8}}$

e)
$\boxed{2\frac{2}{5}:1\frac{1}{5}=\frac{12}{5}:\frac{6}{5}=\frac{12}{5}.\frac{5}{6}=2}$

f)
$\boxed{(\frac{1}{3}+\frac{1}{4}):\frac{1}{2}=(\frac{3+4}{12}):\frac{1}{2}=\frac{7}{12}.\frac{2}{1}=\frac{7}{6}}$

g)
$\boxed{\frac{1+\frac{1}{3}}{3}=\frac{\frac{4}{3}}{3}=\frac{4}{3}.\frac{3}{1}=4}$

h)
$\boxed{\frac{\frac{1+\frac{1}{2}}{2}}{\frac{1}{2}}=\frac{\frac{\frac{3}{2}}{2}}{\frac{1}{2}}=\frac{\frac{3}{2}.\frac{1}{2}}{\frac{1}{2}}=\frac{\frac{3}{4}}{\frac{1}{2}}=\frac{3}{4}.2=\frac{3}{2}}$

i)
$\boxed{\frac{\frac{3}{2}}{1+\frac{2}{3}}=\frac{\frac{3}{2}}{\frac{5}{3}}=\frac{3}{2}.\frac{3}{5}=\frac{9}{10}}$

j)
$\boxed{\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}}{\frac{2}{3}+\frac{3}{4}}:(\frac{9}{17}+1)=\frac{\frac{13}{12}}{\frac{17}{12}}:\frac{26}{17}=\frac{13}{12}.\frac{2}{17}.\frac{17}{26}=\frac{1}{12}}$