Question

(a) x2 + 2x-3=0 Help-me

Answer 1

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+2x-3=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=2~e~c=-3\\\\\Delta=(b)^{2}-4(a)(c)=(2)^{2}-4(1)(-3)=4-(-12)=16\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(2)-\sqrt{16}}{2(1)}=\frac{-2-4}{2}=\frac{-6}{2}=-3\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(2)+\sqrt{16}}{2(1)}=\frac{-2+4}{2}=\frac{2}{2}=1\\\\S=\{-3,~1\}$