Question

a) log 56 Sabendo se que log2=0,30 , log3 = 0,47, log 7 0,84

Answer 1

$log(56) = log( {2}^{3} \times 7 ) \\ log( {2}^{3} ) + log(7) \\ 3 \times log(2) + log(7) \\ 3 \times 0.30 + 0.84 \\ 1.74$