Question

A) √49−√25+√4 B) √49−25+12÷√6+3 Me ajudem pf

Answer 1

Olá

a) $\mathtt{\sqrt{49} -\sqrt{25} +\sqrt{4}}$

Racionalizemos os radicais

$\mathtt{7 - 5 + 2}$

Reduza os valores

$\boxed{\mathtt{4}}$

b) $\mathtt{\dfrac{\sqrt{49-25+12}}{\sqrt{6+3}}}$

Racionalize os valores

$\mathtt{\dfrac{\sqrt{36}}{\sqrt{9}}}$

Racionalize os radicais

$\mathtt{\dfrac{6}{3}}$

Divida os valores

$\boxed{\mathtt{2}}$

Answer 2

$A) 7-5+2=4 \\ \\ R=4 \\ \\ B)7-25+12/ \sqrt{6}+3 \\ \\ 7-25+ \frac{12 \sqrt{6} }{6}+3 \\ \\ 7-25+2 \sqrt{6}+3 \\ \\ R:2 \sqrt{6} -15$