Question

A) -3-³ + 2²
____. =
2-³

B) 3-³+3-²- (-3)-³ =

Answer 1

Resposta:

$a) \ \frac{-3^{-3} + 2^{2}}{2^{-3}} =\\\\\\\frac{-\frac{1}{3^{3}}+4 }{2^{-3}}\\\\\frac{-\frac{1}{27}+4 }{2^{-3}} \\\\\frac{\frac{107}{27} }{2^{-3}}\\ \\\frac{107}{27*2^{-3}}\\ \\\frac{107*2^{3}}{27} \\\\\frac{107*8}{27} \\\\\frac{856}{27}\\ \\= 31,7$

$b) \ 3^{-3} + 3^{-2} - (-3)^{-3}\\\\\frac{1}{3^{3}} + \frac{1}{3^{2}} -(- 3^{-3})\\\\\frac{1}{27}+\frac{1}{9}+ 3^{-3}\\ \\ \frac{4}{27}+\frac{1}{3^{3}}\\ \\ \frac{4}{27}+\frac{1}{27} \\\\\frac{5}{27} \\\\= 0,18$