Question

8) Qual é o oitavo termo da PG
(-1; 4; -16;...)?

Answer 1

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ q = \frac{a2}{a1} = \frac{4}{ - 1} = - 4 \\ \\ \\ an = a1 \times q {}^{n - 1} \\ an = - 1 \times ( - 4) {}^{8 - 1} \\ an = - 1 \times ( - 4) {}^{7} \\ an = - 1 \times ( - 16384) \\ an = 16384 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \leqslant \geqslant \geqslant$