Question

7) se f(x) = \frac{ 1 }{ x ^ { 2 } +1 } ,quanto vale f(-2) - f(2)=​

Answer 1

$f(x) = \frac{1}{x^2 + 1}\\f(-2) = \frac{1}{(-2)^2 + 1} = \frac{1}{4 + 1} = \frac{1}{5}\\f(2) = \frac{1}{2^2 + 1} = \frac{1}{4 + 1} = \frac{1}{5}\\f(-2) - 2= \frac{1}{5} - \frac{1}{5} = 0$